9v^2-11v+2=0

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Solution for 9v^2-11v+2=0 equation: 



9v^2-11v+2=0

a = 9; b = -11; c = +2;
Δ = b2-4ac
Δ = -112-4·9·2
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$


$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-7}{2*9}=\frac{4}{18}
=2/9
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+7}{2*9}=\frac{18}{18}
=1
$

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